| A walks at a uniform speed of 8 km/hr and 8 hours after his start, B starts on his cycle after him at speed of 24km/hr . How far from the starting point will B catch A?
Right Answer is: B
Speed of A=8km/hr
Speed of B=24km/hr
Relative speed of B with respect to A=24-8=16km/hr
Distance covered by A in 8 hour =8× =64km
So time taken by B in catching the A= 64/16=4 hour
So required distance =4× 24=96km