Find the value of sin 2 θ + cosec 2 θ if sinθ + cosecθ = -2 sinθ + 1/s

| Find the value of sin2θ + cosec 2θ if sinθ + cosecθ = -2

A. 1

B. 5

C. 2

D. -4

Right Answer is: C

SOLUTION

sinθ + 1/sinθ = -2
sin2θ + 2sinθ + 1 = 0
(sinθ + 1 )2 = 0
sinθ = -1
sin2θ = 1
cosec2θ = 1
sin2θ + cosec2 θ = 2

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