| If A and B are acute angles such that tanA=1/3 and tanB=1/2 then A+B=?
A. 45
B. 90
C. 60
D. 30
Right Answer is: A
SOLUTION
tanA=1/3
tanB=1/2
tan(A+B)=
substituting values on RHS side,
tan(A+B)==1
Tan(A+B)=tan45
A+B=45
A. 45
B. 90
C. 60
D. 30
tanA=1/3
tanB=1/2
tan(A+B)=
substituting values on RHS side,
tan(A+B)==1
Tan(A+B)=tan45
A+B=45