If in any triangle ABC, the base BC is produced in both ways, the sum

| If in any triangle ABC , the base BC is produced in both ways, the sum of the exterior angles at B and C is :

A. π-A

B. π+A

C. (π/2)+A

D. π

Right Answer is: B

SOLUTION


ABD = π B, ACE = πC
ABD+ACE = 2π -(B+C) = 2π – (π A)
= π + A

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