What is the sum of the squares of all the six numbers? Since a Medi

SOLUTION

Since a<b<c
Median =[(6/2)th term+(6/2+1)th term]/2= (3^rd term+4^th term)/2
2=(b+b)/2 → b=2
Arithmetic mean=(a+a+b+b+c+c)/6
7/3=(a+b+c)/3
a+c=7-2=5
geometric mean=(a²×b²×c²)^1/6
2=(abc)^1/3
abc=8
ac=4
Solving the above equations we get a=1, c=4 and b=2
Required sum=2(1)²+2(2)²+2(4)²=42