| What is the sum of the squares of all the six numbers?

A. 40

B. 42

C. 45

D. 48

### Right Answer is: B

#### SOLUTION

Since a<b<c

Median =[(6/2)th term+(6/2+1)th term]/2= (3^{rd} term+4^{th} term)/2

2=(b+b)/2 → b=2

Arithmetic mean=(a+a+b+b+c+c)/6

7/3=(a+b+c)/3

a+c=7-2=5

geometric mean=(a^{2}×b^{2}×c^{2})^{1/6}

2=(abc)^{1/3}

abc=8

ac=4

Solving the above equations we get a=1, c=4 and b=2

Required sum=2(1)^{2}+2(2)^{2}+2(4)^{2}=42